Category: 思考


Maybe we can be put into a system,and be calculated to be a number。

This number describes what we shall do in next step。

So is there a rational number for a human?

In mathematics, irrational number means non-cycle limitless number.

Since a human is always of limit(his life is limited), he is always a rational number if it can be encoded a number.

(These are 2 different concepts, a human’s limited life and his encoded number’s length are different)

 

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方向、偏差

均可用数字来描述

slope

R^2,这个参数的提出赞点在于是相对的,绝对的不好比较

    明明是个绝对参数,却能找到一个相对参数来衡量

    如何能提出一个指标,是必修的能力之一

预定义偏差范围,就能区分各种方向。

 

问题and答案

有一问题,需要解决方法,即答案。

有各种答案:

  1. 方法a能100%解决它,perfect
  2. 方法b100%不能解决它,也是perfect,至少你晓得一种不work的way,它暗示了此路不通,而且是明确的
  3. 方法c 50%work,50%不work
    这是个麻烦,某种程度上等价于0,似乎一切都回到原点
    但不是这样的
    它暗示了,有些未知的变量还没进入解答者的意识视野

    所以,3需要improve,它需要加入这些被忽视的变量,在此基础上被分裂成类型1,和类型2

question about 0|1 string

If there are 2 specific irrational 01 strings, is there a program which can take these 2 strings as input and output a rational string?

An intuitive answer is yes.

Another qurestion is for any 2 irrational 01 strings, is there a program which can make them to be a rational string?

Furthermore, is there a program to create a program to meet this need?

任给1棵树,都可以用表格来表示。

 

同样,任给1表格,也可以用树来表示。

When talking about speed, we must talk about time。

What is speed?   (speed = a kind of derivative)

  • speed=delta(something)/delta(time)
  • delta(something) = something1 – something0
  • delta(time) = time1 –time0

This is absolute speed.

There is another kind of speed,relative speed.

  • speed=delta(something)/(delta(time)*initial(something))

Take a look at this, http://betterexplained.com/articles/an-intuitive-guide-to-exponential-functions-e/

It gives an excellent explanation of e.

In this article, we only talked about relative speed.  Relative speed = speed.

The e assumes relative speed to be 1.

e = (1+1/n)^n

Assumption:

  1. Start growing at 1
  2. a unit time period T, T=1
  3. The unit time period can splitted into smaller periods
    say N
  4. for its N periods, the relative speed = 1

There are N smaller periods.

  • If the growing counting mechanism is T, then growth only happens once
    We get 2
  • If the growing counting mechanism is T/2, then it grows 2 times
    (1+1/2)
    (1+1/2)(1+1/2)
    We get 2.25
     
  • If the growing counting mechanism is T/3, then it grows 3 times
    (1+1/3)
    (1+1/3)(1+1/3)
    (1+1/3)(1+1/3)(1+1/3)
    We get 1.3^3 = 2.370370…
  •   ……
  • If the growing counting mechanism is T/n, then it grows n times
    … …
    (1+1/n)(1+1/n)….(1+1/n) = (1+1/n)^n

See something here? 3 points here

  • the counting period count be split into smaller periods
                          N * T/N
  • newly growing parts could also grow
  • The growing relative speed keeps being 1 
    delta(something) = ((1+1/n)^n – (1+1/n)^(n-1))=(1+1/n)^(n-1) * 1/n
    delta(time) = 1/n
    initial(something)= (1+1/n)^(n-1)
    delta(something)/(delta(time) * initial(something))=1

This make sense:to get maximum growth we can do something in a smaller period to generate a smaller product but this smaller product can also join the process of growth。

 

 

Let us take a look at another kind of growth. In such kind of growth newly added product does not join the process of growth. Only the initial one grows。

  • If the growing counting mechanism is T, growth only happens 1 time, we get 2
  • If the growing counting mechanism is T/2, then it grows 2 times
    (1+1/2)
    (1+1/2+1/2)
    We get 2
  • If the growing counting mechanism is T/3, then it grows 3 times
    (1+1/3)
    (1+1/3+1/3)
    (1+1/3+1/3+1/3)
    We get 2
  •   ……
  • If the growing counting mechanism is T/n, then it grows n times
    … …
    (1+1/n+1/n+…+1/n)   1/n exists n times
    We get 2

Such kind of growth relative speed is not constant for its N periods when considering newly added parts。However when not considering newly added parts, its relative speed is 1.

空调

空调是1个打破平衡的玩意

它将某个密闭空间的热量抽出,转移到公共空间

密闭空间的人得以享受合适温度,问题得以解决,外部空间的人只能是更热,问题不仅没有解决,反而是扩大了

所以当空调这玩意出现时,它是有生命力的,即使是仅仅解决了某个局部空间的合适温度问题。  

使用它着爽,不用它反而更加剧了。

能打破平衡,的确是一种超能力。

 

花钱有时也是1个方法。

很显然,第一步是建立函数关系。

你关心哪些因素,如何量化这些因素;关心的因素放在右边。假设只有1个因素Y,

再寻找其他影响Y的因素,假设只有1个因素X,

Y和X之间的关系是否很显然?  很容易发现的就是线性了,不容易发现的就是非线性的了。

一句话,Y=f(X)

f如何描述是个问题。

Y有时不止1个,X有时也不止1个也是问题。

遇到实际问题,你是否能想到建立函数关系来解决也是个问题。

就算想到这条路,是否能建立起贴合实际的函数关系也是个问题。

就算能找到合适的函数关系,是否有足够的资源来落实这个关系有时也是个问题。

是否需要找若干X的实例x们,Y的实例y们来发现函数关系也是问题。

还有一种情况是f这个关系也会变,它是时间的函数

note(2015/06/22):

  1. http://www.oecd.org/pisa/keyfindings/pisa-2012-results-overview.pdf
  2. http://data.163.com/15/0608/07/ARIOOEGN00014MTN.html

 

If … now, then …

遇到困难时,应该多问问自己这个问题

  • 如果现在what成立,那么结果会如何?

what当然不会是现成就摆在你面前的,问题是

  • 你如何发现这个what
  • 是否能找到坐实what的路